将csv文件数据导入数据库

我必须写一个代码，我需要导入人的电子邮件ID与他们的名字将在Excel表到数据库中，但是面临的问题是它显示我无效的文件，其中作为文件的.csv格式请帮助，对这个概念是新的，如果我在某个地方出错了，请原谅我。

import.php

<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" enctype="multipart/form-data"> <input type="file" name="sel_file" size="20" /><br /> <input type="submit" name="submit" value="Submit" /> </form> <?php include ("connection.php"); if(isset($_POST["submit"])) { $fname = $_FILES['sel_file']['tmp_name']; echo'Upload file name is'.$fname.' '; $chk_ext = explode(".",$fname); if(strtolower(end($chk_ext)) == "csv"){ $filename = $_FILES['sel_file'] ['tmp_name']; $handle = fopen($filename, "r"); while(($data = fgetcsv($handle, 1000, ",")) !== false) { $sql = "INSERT into import_email (vault_no, name, email) values ('".$_SESSION['vault_no']."', '$data[0]', '$data[1]')"; mysql_query($sql) or die(mysql_error()); } fclose($handle); echo "Successfully imported! "; }else{ echo "Invalid file!"; } } ?> 

Answer 1

您正在使用临时名称而不是名称

  $_FILES['sel_file'] ['tmp_name']; 

将其更改为：

  $_FILES['sel_file'] ['name']; 

$_FILE['input_file']例子是

 [input_file] => Array ( [name] => MyFile.jpg //<-------- This is the one you should use because it contains the extension (that you are checking for) [type] => image/jpeg [tmp_name] => /tmp/php/php6hst32 //<----------- this is the one you used [error] => UPLOAD_ERR_OK [size] => 98174 ) 

所以你的PHP部分应该是这样的：

  <?php include("connection.php"); if (isset($_POST["submit"])) { $fname = $_FILES['sel_file']['name']; // Changed only this echo 'Upload file name is' . $fname . ' '; $chk_ext = explode(".", $fname); if (strtolower(end($chk_ext)) == "csv") { $filename = $_FILES['sel_file'] ['tmp_name']; $handle = fopen($filename, "r"); while (($data = fgetcsv($handle, 1000, ",")) !== false) { $sql = "INSERT into import_email (vault_no, name, email) values ('" . $_SESSION['vault_no'] . "', '$data[0]', '$data[1]')"; mysql_query($sql) or die(mysql_error()); } fclose($handle); echo "Successfully imported! "; } else { echo "Invalid file!"; } } ?>