R:如何将结构化列表导出为ex​​cel

这应该是非常简单的,但我的努力与unlistmatrix失败。

如何将以下列表导出到保留相同结构的Excel表格中?

 list(structure(list(rob = c(0.500395231401348, 0.839314035292317, 0.710466394967634, 0.61574235723249)), .Names = "rob", row.names = c(NA, 4L), class = "data.frame"), structure(list(rob = c(0.66163340478379, 0.591092739290417, 0.554484883310407, 0.78199375944331, 0.489388775242085 )), .Names = "rob", row.names = c(NA, 5L), class = "data.frame"), structure(list(rob = c(0.697897964659196, 0.480394119894312, 0.514294379103359, 0.626971885076273, 0.77938643423231, 0.618135503224601 )), .Names = "rob", row.names = c(NA, 6L), class = "data.frame")) 

谢谢!

你可以这样做:

  1. NA填充每个vector,使所有vector的长度相同
  2. 使用do.call(rbind, ...)创build数据框

喜欢这个:

 xx <- lapply(x, unlist) max <- max(sapply(xx, length)) do.call(rbind, lapply(xx, function(z)c(z, rep(NA, max-length(z))))) rob1 rob2 rob3 rob4 [1,] 0.5003952 0.8393140 0.7104664 0.6157424 NA NA [2,] 0.6616334 0.5910927 0.5544849 0.7819938 0.4893888 NA [3,] 0.6978980 0.4803941 0.5142944 0.6269719 0.7793864 0.6181355 

那么这是一个简单的使用write.table()或你最喜欢的导出到Excel的方法write.table()