我试图从Excel文件中读取后保存在Postgres表中的数据。当试图提交，我得到一个铸造错误

模型类

package test1; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.Table; @Entity @Table(name="employee_details") public class Employee { @Id private String emp_id; private String emp_name; private String location; public String getEmp_id() { return emp_id; } public void setEmp_id(String emp_id) { this.emp_id = emp_id; } public String getEmp_name() { return emp_name; } public void setEmp_name(String emp_name) { this.emp_name = emp_name; } public String getLocation() { return location; } public void setLocation(String location) { this.location = location; } } 

数据库表格脚本

  CREATE TABLE mytestschema.employee_details ( emp_id character varying(255), emp_naame character varying(255), location character varying(255) ) WITH ( OIDS=FALSE ); ALTER TABLE mytestschema.employee_details OWNER TO postgres; 

Hibernate的cfg文件

  <?xml version='1.0' encoding='UTF-8'?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <property name="dialect">org.hibernate.dialect.PostgreSQLDialect</property> <property name="connection.url">jdbc:postgresql://localhost:5432/postgres</property> <property name="connection.username">postgres</property> <property name="connection.password">root</property> <property name="connection.driver_class">org.postgresql.Driver</property> <property name="show_sql">true</property> <property name="format_sql">true</property> <mapping class="test1.Employee"/> </session-factory> </hibernate-configuration> 

主要类

  package test1; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.util.ArrayList; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import org.apache.poi.hssf.usermodel.HSSFSheet; import org.apache.poi.hssf.usermodel.HSSFWorkbook; import org.apache.poi.ss.usermodel.Cell; import org.apache.poi.ss.usermodel.Row; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.Transaction; import org.hibernate.cfg.Configuration; public class test2 { static List<Employee> empList = new ArrayList<Employee>(); static List<String> valueHolder = new ArrayList<String>(); public static void main(String[] args) { List<Employee> list = readExcel("D:\\test.xls"); persistToDB(list); } private static List<Employee> readExcel(String filepath) { try { FileInputStream file = new FileInputStream(new File("D:\\test.xls")); HSSFWorkbook workbook = new HSSFWorkbook(file); HSSFSheet sheet = workbook.getSheetAt(0); for (int i = 1; i <= sheet.getLastRowNum(); i++) { Row row = sheet.getRow(i); for (int j = 0; j < row.getLastCellNum(); j++) { Cell cell = row.getCell(j); valueHolder.add(cell.toString()); } } for(int i = 0; i < valueHolder.size(); i+=3){ String first = valueHolder.get(i); String second = null; String third = null; if(valueHolder.size() > i + 2){ second = valueHolder.get(i + 1); third = valueHolder.get(i+2); System.out.println("First [" + first + "] - Second [" + second + "] - Third [" +third +"]"); Employee employee = new Employee(); employee.setEmp_id(first); employee.setEmp_name(second); employee.setLocation(third); empList.add(employee); } } } catch (FileNotFoundException fnfe) { fnfe.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return empList; } @SuppressWarnings("deprecation") private static void persistToDB(List<Employee> employees) { Configuration c = new Configuration(); c.configure("/hibernate.cfg.xml"); SessionFactory sf = c.buildSessionFactory(); Session s = sf.openSession(); Transaction tx = s.beginTransaction(); try { for (int i = 0; i < employees.size(); i++) { Employee emp = employees.get(i); s.save(emp); } tx.commit(); s.close(); } catch (Exception e) { tx.rollback(); } } } 

当试图运行这个代码时，我收到以下错误

  14:19:17.114 [main] DEBUG ohejdbc.spi.SqlExceptionHelper - could not execute statement [n/a] org.postgresql.util.PSQLException: ERROR: column "emp_id" is of type integer but expression is of type character varying Hint: You will need to rewrite or cast the expression. Position: 75 at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2102) ~[postgresql-9.1-901.jdbc4.jar:na] at org.postgresql.core.v3.QueryExecutorImpl.processResults(QueryExecutorImpl.java:1835) ~ [postgresql-9.1-901.jdbc4.jar:na] at org.postgresql.core.v3.QueryExecutorImpl.execute(QueryExecutorImpl.java:257) ~ [postgresql-9.1-901.jdbc4.jar:na] at org.postgresql.jdbc2.AbstractJdbc2Statement.execute(AbstractJdbc2Statement.java:500) ~[postgresql-9.1-901.jdbc4.jar:na] at org.postgresql.jdbc2.AbstractJdbc2Statement.executeWithFlags(AbstractJdbc2Statement.java:38 8) ~[postgresql-9.1-901.jdbc4.jar:na] at org.postgresql.jdbc2.AbstractJdbc2Statement.executeUpdate(AbstractJdbc2Statement.java:334) ~[postgresql-9.1-901.jdbc4.jar:na] at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:133) ~[hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.engine.jdbc.batch.internal.NonBatchingBatch.addToBatch(NonBatchingBatch.java: 58) ~[hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3067) ~[hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3509) ~[hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:88) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:364) [hibernate- core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:356) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:277) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:328) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:52) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1234) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:404) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:175) [hibernate-core-4.2.1.Final.jar:4.2.1.Final] at test1.test2.persistToDB(test2.java:87) [classes/:na] at test1.test2.main(test2.java:28) [classes/:na] 14:19:17.114 [main] WARN ohejdbc.spi.SqlExceptionHelper - SQL Error: 0, SQLState: 42804 14:19:17.114 [main] ERROR ohejdbc.spi.SqlExceptionHelper - ERROR: column "emp_id" is of type integer but expression is of type character varying Hint: You will need to rewrite or cast the expression. Position: 75 14:19:17.115 [main] DEBUG ohetspi.AbstractTransactionImpl - rolling back 14:19:17.116 [main] DEBUG ohetijdbc.JdbcTransaction - rolled JDBC Connection 

列“emp_id”是不是在表中的整数types，但我无法找出为什么这个错误即将到来，请有人请帮助。