在SQL Server 2008 R2上将列转置为行
我写了一个查询，需要使用从asp.net SQL命令导出到Excel文件，但首先，我只是想转置列行我试图使用数据透视，但它不工作
我写这样的查询
SELECT CATAGORY_NAME,GROUP_NAME,FUNCTION_NAME,'G'+TEST_CASE.GID + '-TC'+TEST_CASE.CASE_ID CASE_ID,CASE_NAME,CASE_NAME_TH,EXPECT_RESULT,EXPECT_DETAIL,INTERFACE,RESULT,TEST_DATE,TEST_BY,REMARK FROM TEST_CASE LEFT OUTER JOIN TEST_CATAGORY ON TEST_CASE.CID = TEST_CATAGORY.CID AND TEST_CASE.SID = TEST_CATAGORY.SID LEFT OUTER JOIN TEST_GROUP ON TEST_CASE.GID = TEST_GROUP.GID AND TEST_CASE.CID = TEST_GROUP.CID WHERE TEST_CASE.SID = 1 ORDER BY TEST_CASE.CID 它工作正常，我需要通过CATAGORY NAME转移它们
从（例如所有因为有很多列）
CATAGORY_NAME GROUP_NAME FUNCTION_NAME CASE_ID TS12345 TDAS NOS 1234 CATAGORY_NAME GROUP_NAME FUNCTION_NAME CASE_ID TS12346 TDAF NOS 1235
至
CATAGORY NAME TS12345 GROUP NAME TDAS FUNCTION NAME NOS CASE ID 1234 CATAGORY NAME TS12346 GROUP NAME TDAF FUNCTION NAME NOS CASE ID 1235
来自查询的表数据
CATAGORY_NAME GROUP_NAME FUNCTION_NAME CASE_ID CASE_NAME EXPECT_RESULT INTERFACE RESULT TEST_DATE TEST_BY REMARK Desbes Optivy TESTING125 FAST CASH G01-TC00101 Fast Rejected VISA N/R 12-ธ.ค.-14 Tester1 4012999971111142 4012999971111142 IBM Omron ADM3 (S1G366932) VISA Chip (Single App) FAST CASH G03-TC00501 Fast Approved VISA PASS 11-ธ.ค.-14 Tester1 4761340000000035 4761340000000035 Wincor PC280 (S1A365305) Abnormal SCB Card Abnormal Fast cash G28-TC11804 Inactive status Rejected CBS PASS 25-ธ.ค.-14 tester3 5.57755E+15 Wincor PC280 (S1A365305) Abnormal VISA Magnetic Abnormal Withdrawal G30-TC15402 Do not input amount Rejected #NAME? BASE24 PASS tester3
TB TEST_CASE
SID CID GID CASE_ID FUNCTION_NAME CASE_NAME CASE_NAME_TH TEST_CARD CONDITION EXPECT_RESULT ACTUAL_RESULT SEQ TEST_BY TEST_DATE REMARK RESULT INTERFACE TEMPLATE_NAME RETEST_DATE 1 1 1 101 FAST CASH Fast cash - 200 FASTCAS 12345 NULL Rejected Approved 20-21 TESTER1 12-ธ.ค.-14 TEST N/R VISA Recycle ;PN13 Jan 15 1 1 1 102 FAST CASH Fast cash - 500 FASTCAS 12345 NULL Approved Approved 22-23 TESTER2 12-ธ.ค.-14 TEST PASS VISA Recycle NULL 1 1 1 103 FAST CASH Fast cash - 1,000 FASTCAS 12345 NULL Approved Approved 26-27 TESTER3 12-ธ.ค.-14 TEST PASS VISA Recycle NULL
TB TEST_CATAGORY
SID CID CATAGORY_NAME INFO_1 INFO_2 INFO_3 INFO_4 INFO_5 TEMPLATE_NAME INFO_L1 INFO_L2 INFO_L3 INFO_L4 INFO_L5 1 1 Diebold Optiva378 (S1G366937) S1G366937 Diebold Win7 $DATA.AT401000.CDMD3IN1 Optiva378 Recycle Term Vendor OS CI File NULL 1 2 NCR S6622E (S1G365311) S1G365311 NCR Win7 $DATA.AT40N50. CI587IPF S6622E ATM Full Term Vendor OS CI File NULL 1 3 Wincor PC1500XE (S1A365303) S1A365303 Wincor XP $DATA.AT401000. CIWINCOR PC 1500XE ATM Partial Term Vendor OS CI File NULL 1 4 IBM Nautilus CD4 (S1G365306) S1G365306 IBM XP $DATA.AT401000. OMIP02 Nautilus ATM Partial Term Vendor OS CI File NULL
TB TEST_GROUP
SID CID GID GROUP_NAME GROUP_CODE TEMPLATE_NAME 1 01 VISA Magnetic NULL ATM Full 1 01 VISA Magnetic NULL ATM Multi 1 01 VISA Magnetic NULL ATM Partial 1 01 VISA Magnetic NULL Existing ATM 1 01 VISA Magnetic NULL Existing CDM 1 01 VISA Magnetic NULL Existing Multi 1 01 VISA Magnetic NULL Existing Recycle 1 01 VISA Magnetic NULL Recycle 1 02 VISA Chip-Fallback NULL ATM Full 1 02 VISA Chip-Fallback NULL ATM Multi 1 02 VISA Chip-Fallback NULL ATM Partial 1 02 VISA Chip NULL Existing ATM 1 02 VISA Chip NULL Existing CDM 1 02 VISA Chip NULL Existing Multi 1 02 VISA Chip NULL Existing Recycle 1 02 VISA Chip-Fallback NULL Recycle 1 03 VISA Chip (Single App) NULL ATM Full 1 03 VISA Chip (Single App) NULL ATM Multi 1 03 VISA Chip (Single App) NULL ATM Partial 1 03 MDS Magnetic NULL Existing ATM 1 03 MDS Magnetic NULL Existing CDM 1 03 MDS Magnetic NULL Existing Multi 1 03 MDS Magnetic NULL Existing Recycle 1 03 VISA Chip (Single App) NULL Recycle 1 04 VISA Chip (Multi App) NULL ATM Full 1 04 VISA Chip (Multi App) NULL ATM Multi 1 04 VISA Chip (Multi App) NULL ATM Partial 1 04 MDS Chip NULL Existing ATM 1 04 MDS Chip NULL Existing CDM 1 04 MDS Chip NULL Existing Multi 1 04 MDS Chip NULL Existing Recycle 1 04 VISA Chip (Multi App) NULL Recycle 1 05 MDS Magnetic NULL ATM Full
尝试这个
SELECT 'CATAGORY_NAME' COL,CATAGORY_NAME FROM Yourtable UNION ALL SELECT 'GROUP_NAME',GROUP_NAME FROM Yourtable UNION ALL SELECT 'FUNCTION_NAME',FUNCTION_NAME FROM Yourtable UNION ALL SELECT 'CASE_ID',CASE_ID FROM Yourtable
编辑：
对于您更新的问题，可以遵循以下方法。
样品表
CREATE TABLE #TEMP(CATAGORY_NAME VARCHAR(200),GROUP_NAME VARCHAR(200), FUNCTION_NAME VARCHAR(200),CASE_ID VARCHAR(200)) INSERT INTO #TEMP SELECT 'Desbes Optivy', 'TESTING125', 'FAST CASH' , 'G01-TC00101' UNION ALL SELECT 'IBM Omron ADM3 (S1G366932)', 'VISA Chip (Single App)', 'FAST CASH', 'G03-TC00501' UNION ALL SELECT 'Wincor PC280 (S1A365305)', 'Abnormal SCB Card', 'Abnormal Fast cash', 'G28-TC11804' UNION ALL SELECT 'Wincor PC280 (S1A365305)', 'Abnormal VISA Magnetic', 'Abnormal Withdrawal', 'G30-TC15402'
QUERY
;WITH CTE AS ( -- Here we get a unique id for each row SELECT ROW_NUMBER() OVER(ORDER BY (SELECT(0))) RNO,* FROM #TEMP ) ,CTE2 AS ( -- Hardcode the column names SELECT 'CATAGORY NAME' COL,CATAGORY_NAME,RNO FROM CTE UNION ALL SELECT 'GROUP NAME',GROUP_NAME,RNO FROM CTE UNION ALL SELECT 'FUNCTION NAME',FUNCTION_NAME,RNO FROM CTE UNION ALL SELECT 'CASE ID',CASE_ID,RNO FROM CTE ) -- Select all the data and order by a column according to our logic -- Row number gets you unique id for each rows SELECT * FROM CTE2 ORDER BY RNO, CASE WHEN COL = 'CATAGORY NAME' THEN 1 WHEN COL = 'GROUP NAME' THEN 2 WHEN COL = 'FUNCTION NAME' THEN 3 WHEN COL = 'CASE ID' THEN 4 END
编辑2：
试试这个
;WITH CTE AS ( SELECT ROW_NUMBER() OVER(ORDER BY TEST_CASE.CID) RNO, CATAGORY_NAME,GROUP_NAME,FUNCTION_NAME, 'G'+TEST_CASE.GID + '-TC'+TEST_CASE.CASE_ID CASE_ID, CASE_NAME,CASE_NAME_TH,EXPECT_RESULT,EXPECT_DETAIL, INTERFACE,RESULT,TEST_DATE,TEST_BY,REMARK FROM TEST_CASE LEFT OUTER JOIN TEST_CATAGORY ON TEST_CASE.CID = TEST_CATAGORY.CID AND TEST_CASE.SID = TEST_CATAGORY.SID LEFT OUTER JOIN TEST_GROUP ON TEST_CASE.GID = TEST_GROUP.GID AND TEST_CASE.CID = TEST_GROUP.CID WHERE TEST_CASE.SID = 1 ) ,CTE2 AS ( -- Hardcode the column names SELECT 'CATAGORY NAME' COL,CATAGORY_NAME,RNO FROM CTE UNION ALL SELECT 'GROUP NAME',GROUP_NAME,RNO FROM CTE UNION ALL SELECT 'FUNCTION NAME',FUNCTION_NAME,RNO FROM CTE UNION ALL SELECT 'CASE ID',CASE_ID,RNO FROM CTE ) -- Select all the data and order by a column according to our logic -- Row number gets you unique id for each rows SELECT * FROM CTE2 ORDER BY RNO, CASE WHEN COL = 'CATAGORY NAME' THEN 1 WHEN COL = 'GROUP NAME' THEN 2 WHEN COL = 'FUNCTION NAME' THEN 3 WHEN COL = 'CASE ID' THEN 4 END
我将使用Cross apply来解决这个问题
SELECT column_name, data FROM result CROSS apply (VALUES ('CATAGORY_NAME',CATAGORY_NAME), ('GROUP_NAME',GROUP_NAME), ('FUNCTION_NAME',FUNCTION_NAME), ('CASE_ID',CONVERT(VARCHAR(50), CASE_ID))) cs(column_name, data)
SQLFIDDLE DEMO