如果在SQL语句中计算年龄
我在SQL方面很新，我一直在研究我的第一个查询。 现在我需要你的帮助。 我在Excel中有这个报告。 我在计算AGE的AGE列中有公式。 我一直在试图创build一个SQL查询来拿出相同的答案。 到目前为止，我已经想出了我需要的列，并将所有数据都拉到匹配Excel。 唯一的是我不知道如何以及在哪里进入这个IF语句，所以它会计算我运行查询的年龄。
Work Order Location MISC Status Actual Finish Finish Time Parent WO Work Type N Reported Date Reported Time Site Gen Age Sub Name Substation Location 1234567899 4074 COMP 11/5/14 3:08:49 PM CM 10/7/14 1:47:42 PM 29.05633102 12348574987 2946 SCHED CM 10/30/14 10:28:03 AM 188.5638542 AGE是一个公式，粘贴在下面：
=IF ((IF(Status<>"Comp",Today()-Reported date, actual finish-reported date))<0,0, IF(STATUS<>"COMP", TODAY()-REPORTED DATE, ACTUAL FINISH-REPORTED DATE))
SQL写入查询
SELECT WO.WONUM, LOCOFFDESC.DESCRIPTION AS OFFICE, WO.STATUS, WO.LOCATION, CASE WHEN ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 2, 3)) = 0) THEN SUBSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 1, 2) + 2)), LENGTH(LOCOFF.EXT_LOC_HIERARCHY_PATH)) WHEN ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 2, 3)) IS NOT NULL) THEN SUBSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 1, 2) + 2)), (INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 2, 3)) - (INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 1, 2) + 2)) END AS "SUBSTATION CASE", WO.PARENT, WO.WORKTYPE, WO.REPORTEDBY, WO.REPORTDATE, WO.ACTFINISH, WO.SITEID FROM LOCATIONS LOCOFF RIGHT JOIN MAXPRD.WORKORDER WO ON WO.LOCATION = LOCOFF.LOCATION INNER JOIN MAXPRD.LOCANCESTOR LOCOFFANC ON LOCOFFANC.LOCATION = LOCOFF.LOCATION INNER JOIN MAXPRD.LOCATIONS LOCOFFDESC ON LOCOFFANC.ANCESTOR = LOCOFFDESC.LOCATION INNER JOIN MAXPRD.LOCHIERARCHY LOCOFFHIER ON LOCOFFANC.ANCESTOR = LOCOFFHIER.LOCATION WHERE LOCOFF.SITEID = 'SUB' AND LOCOFFHIER.PARENT = '2000' GROUP BY WO.WONUM, LOCOFFDESC.DESCRIPTION, WO.STATUS, WO.LOCATION, LOCOFF.EXT_LOC_HIERARCHY_PATH, LOCOFF.SITEID, LOCOFFHIER.PARENT, WO.PARENT, WO.WORKTYPE, WO.REPORTEDBY, WO.REPORTDATE, WO.ACTFINISH, WO.SITEID
您将计算放在SELECT语句之后，在FROM语句之前，所以您有一个填充了计算值的列，类似于Excel。
我们需要知道你正在使用哪个数据库系统来获得确切的语法。 你可以尝试一下WO.SITEID，
SELECT WO.WONUM, LOCOFFDESC.DESCRIPTION AS OFFICE, WO.STATUS, WO.LOCATION, CASE WHEN ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 2, 3)) = 0) THEN SUBSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 1, 2) + 2)), LENGTH(LOCOFF.EXT_LOC_HIERARCHY_PATH)) WHEN ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 2, 3)) IS NOT NULL) THEN SUBSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, ((INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 1, 2) + 2)), (INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 2, 3)) - (INSTR(LOCOFF.EXT_LOC_HIERARCHY_PATH, '/', 1, 2) + 2)) END AS "SUBSTATION CASE", WO.PARENT, WO.WORKTYPE, WO.REPORTEDBY, WO.REPORTDATE, WO.ACTFINISH, WO.SITEID, ( CASE WHEN ( CASE WHEN WO.STATUS != 'Comp' THEN SYSDATE-WO.REPORTDATE ELSE WO.ACTFINISH-WO.REPORTDATE END) < 0 THEN 0 ELSE CASE WHEN STATUS != 'COMP' THEN SYSDATE-WO.REPORTDATE ELSE WO.ACTFINISH-WO.REPORTDATE END END) as age FROM LOCATIONS LOCOFF RIGHT JOIN MAXPRD.WORKORDER WO ON WO.LOCATION = LOCOFF.LOCATION INNER JOIN MAXPRD.LOCANCESTOR LOCOFFANC ON LOCOFFANC.LOCATION = LOCOFF.LOCATION INNER JOIN MAXPRD.LOCATIONS LOCOFFDESC ON LOCOFFANC.ANCESTOR = LOCOFFDESC.LOCATION INNER JOIN MAXPRD.LOCHIERARCHY LOCOFFHIER ON LOCOFFANC.ANCESTOR = LOCOFFHIER.LOCATION WHERE LOCOFF.SITEID = 'SUB' AND LOCOFFHIER.PARENT = '2000' GROUP BY WO.WONUM, LOCOFFDESC.DESCRIPTION, WO.STATUS, WO.LOCATION, LOCOFF.EXT_LOC_HIERARCHY_PATH, LOCOFF.SITEID, LOCOFFHIER.PARENT, WO.PARENT, WO.WORKTYPE, WO.REPORTEDBY, WO.REPORTDATE, WO.ACTFINISH, WO.SITEID
为MS SQL服务器编辑。 再次为Oracle编辑:)