Python34 NMEA语句使用xlsxwriter放入xlsx中
我正在做一个nmea句子项目，在那里我得到一个由逗号分隔的nmea句子的txt文件。 我试图用xlsxwriter把结果写入excel。 我想要的结果是有时间戳，纬度，经度和海拔高度印刷在彼此对应的行…但我不断得到我的“查询”的第一次迭代写出五次之前，其他迭代写入xlsx。 我知道这一定是一个简单的解决scheme..你能告诉我我要去哪里吗？
这是我的脚本的开始，所以您可以全面了解正在发生的事情
import os import csv from csv import * import numpy import matplotlib from numpy import * from matplotlib import * import matplotlib.pyplot as plt from matplotlib.pylab import * import numpy as np #to export to excel import xlsxwriter from xlsxwriter.workbook import Workbook #to get the csv converter functions import os import subprocess import glob #to get the datetime functions import datetime from datetime import datetime from pytz import timezone import time import calendar #creates the path needed for incoming and outgoing files path_in = 'C:/Python34/gps_txts/' path_out = 'C:/Python34/output_files/' #prints all the data in the file if you want q_show_content = input('Print list of files type y:') if q_show_content == 'y': for root, dirs, files in os.walk(path_in): print(root, dirs, files) else: print('ok') data = [] #empty because we will store data into it #Reads a CSV file and return it as a list of rows def read_csv_file(filename): """Reads a CSV file and return it as a list of rows.""" for row in csv.reader(open(filename)): data.append(row) return data #request of what file to look at print ("- - - - - - - - - - - - -") data_file = input('Which file do you want to look at?') f = open(path_in + data_file) read_it = read_csv_file(path_in + data_file) with f as csvfile: readCSV = csv.reader(csvfile,delimiter=',') plots = csv.reader(csvfile, delimiter=',') #creates the workbook output_filename = input('output filename:') workbook = xlsxwriter.Workbook(path_out + output_filename + '.xlsx') worksheet = workbook.add_worksheet() #formatting definitions bold = workbook.add_format({'bold': True}) date_format = workbook.add_format({'num_format': "m/d/yyyy hh:mm:ss"}) #print number of rows print ("- - - - - - - - - - - - -") rows = len(read_it) print (data_file, " has "+ str(rows) + " rows of data") print ("- - - - - - - - - - - - -") #Counts the number of times a GPS command is observed def list_gps_commands(data): """Counts the number of times a GPS command is observed. Returns a dictionary object.""" gps_cmds = dict() for row in data: try: gps_cmds[row[0]] += 1 except KeyError: gps_cmds[row[0]] = 1 return gps_cmds print(list_gps_commands(read_it)) print ("- - - - - - - - - - - - -") #prints all the data in the file if you want q_show_data = input('Print data inside ' + data_file + ' type y:') if q_show_data == 'y': for row in read_it: print(row) else: print('ok') 这是我遇到问题的部分
#Function process_gps_data for GPS NMI = 1852.0 def process_gps_data(data): """Processes GPS data, NMEA 0183 format. Returns a tuple of arrays: latitude, longitude, velocity [km/h], time [sec] and number of satellites. See also: http://www.gpsinformation.org/dale/nmea.htm. """ latitude = [] longitude = [] altitude = [] velocity = [] timestamp = [] num_sats = [] for row in data: if row[0] == '$GPRMC': # Valid position/time sentence y = (float(row[3][0:2]) + float(row[3][2:])/60.0) if row[4] == "S": y = -y latitude.append(y) x = (float(row[5][0:3]) + float(row[5][3:])/60.0) if row[6] == "W": x = -x longitude.append(x) print('x,y:',x,y) velocity.append(float(row[7])*NMI/1000.0) gpstime = row[1][0:6] # hhmmss gdate = row[9] # ddmmyy gpsdate = gdate[4:6]+gdate[2:4]+gdate[0:2] # yymmdd real_time =gpsdate + gpstime add_date_time = datetime.strptime(real_time, "%y%m%d%H%M%S") print(add_date_time) timestamp.append(add_date_time) return (array(latitude), array(longitude), array(velocity), array(timestamp)) # how to call process_gps_data() (lati, long, v, t_stamp) = process_gps_data(data) print ("- - - - - - - - - - - - -") print('lati:',lati) print ("- - - - - - - - - - - - -") print('long:',long) print ("- - - - - - - - - - - - -") print('v:',v) print ("- - - - - - - - - - - - -") print('date:', t_stamp) print ("- - - - - - - - - - - - -") #sets up the header row worksheet.write('A1','TimeStamp',bold) worksheet.write('B1', 'Latitude',bold) worksheet.write('C1', 'Longitude',bold) worksheet.write('D1', 'Velocity',bold) worksheet.autofilter('A1:D1') #dropdown menu created for filtering # Create a For loop to iterate through each row in the XLS file, starting at row 2 to skip the headers for r, row in enumerate(data, start=1): #where you want to start printing results inside workbook for c, col in enumerate(row): worksheet.write_column(r,0, t_stamp, date_format) worksheet.write_column(r,1, lati) worksheet.write_column(r,2, long) worksheet.write_column(r,3, v) workbook.close() f.close()
我正在使用这些行在一个txt文件的虚拟GPScaching。 注意到GPRMC在行[9] == 01,02,03有不同的年份
$GPRMC,002454,A,3553.5295,N,13938.6570,E,0.0,43.1,180701,7.1,W,A*3F $GPRMB,A,,,,,,,,,,,,A,A*0B $GPGGA,002455,3553.5295,N,13938.6570,E,1,05,2.2,18.3,M,39.0,M,,*7F $GPRMC,002456,A,3553.5321,N,13938.6581,E,0.0,43.1,180702,7.1,W,A*3D $GPRMC,104715.20,A,5100.2111,N,00500.0006,E,21.7,003.0,140803,01.,W*70
我的结果被打印出来，看起来他们预期的方式…
- - - - - - - - - - - - - garmin etrex summit.txt has 5 rows of data - - - - - - - - - - - - - {'$GPRMC': 3, '$GPGGA': 1, '$GPRMB': 1} - - - - - - - - - - - - - Print data inside garmin etrex summit.txt type y: ok x,y: 139.64428333333333 35.892158333333334 2000-07-18 00:24:54 x,y: 139.64430166666668 35.892201666666665 2001-07-18 00:24:56 x,y: 5.00001 51.00351833333333 2003-08-14 10:47:15 - - - - - - - - - - - - - lati: [ 35.89215833 35.89220167 51.00351833] - - - - - - - - - - - - - long: [ 139.64428333 139.64430167 5.00001 ] - - - - - - - - - - - - - v: [ 0. 0. 40.1884] - - - - - - - - - - - - - date: [datetime.datetime(2000, 7, 18, 0, 24, 54) datetime.datetime(2001, 7, 18, 0, 24, 56) datetime.datetime(2003, 8, 14, 10, 47, 15)] - - - - - - - - - - - - -
但是，当我看着我生产的xlsx文件，我有前五行看起来像这样：
TimeStamp Latitude Longitude Velocity 7/18/2001 00:24:54 35.89215833 139.6442833 0 7/18/2001 00:24:54 35.89215833 139.6442833 0 7/18/2001 00:24:54 35.89215833 139.6442833 0 7/18/2001 00:24:54 35.89215833 139.6442833 0 7/18/2001 00:24:54 35.89215833 139.6442833 0 7/18/2002 00:24:56 35.89220167 139.6443017 0 8/14/2003 10:47:15 51.00351833 5.00001 40.1884
所以我的问题是，我得到了5个相同的第一个'查询'，然后'$ GPRMC'的另外两个迭代
我哪里错了？