错误Python – 214702489访问被拒绝（COM）更新
我正在尝试使用Web应用程序Flask / Python在excel中启动一个macros，当用户按下button后面的过程时打开一个excel做一个macros并返回结果。
如果我使用IDE Visual Studio 2015来做这件事情，那就没有问题了，当我尝试使用IIS时（发布），我可以导航到Web应用程序，但是当我按下button时，出现这个错误：
Error occurred: Traceback (most recent call last): File "C:\inetpub\wwwroot\MyWebSite\wfastcgi.py", line 736, in main result = handler(record.params, response.start) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1836, in __call__ return self.wsgi_app(environ, start_response) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1820, in wsgi_app response = self.make_response(self.handle_exception(e)) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1403, in handle_exception reraise(exc_type, exc_value, tb) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1817, in wsgi_app response = self.full_dispatch_request() File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1477, in full_dispatch_request rv = self.handle_user_exception(e) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1381, in handle_user_exception reraise(exc_type, exc_value, tb) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1475, in full_dispatch_request rv = self.dispatch_request() File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1461, in dispatch_request return self.view_functions[rule.endpoint](**req.view_args) File ".\QPX_Test\upload.py", line 62, in upload process_excel.up_route(variable_forsave, 'C:\Tool_OP14\System\Main System FIndx', 'System','B1') File ".\QPX_Test\process_excel.py", line 27, in up_route xlApp = win32com.client.Dispatch('Excel.Application') File "C:\Anaconda2\lib\site-packages\win32com\client\__init__.py", line 95, in Dispatch dispatch, userName = dynamic._GetGoodDispatchAndUserName(dispatch,userName,clsctx) File "C:\Anaconda2\lib\site-packages\win32com\client\dynamic.py", line 114, in _GetGoodDispatchAndUserName return (_GetGoodDispatch(IDispatch, clsctx), userName) File "C:\Anaconda2\lib\site-packages\win32com\client\dynamic.py", line 91, in _GetGoodDispatch IDispatch = pythoncom.CoCreateInstance(IDispatch, None, clsctx, pythoncom.IID_IDispatch) com_error: (-2147024891, 'Access is denied.', None, None) StdOut: StdErr: 我尝试了一切：
安全文件夹（C：\ inetpub \ wwwroot）我添加了具有完全权限的IUSR用户，与PCNAME \ IIS_IUSRS和我的Web应用程序（应用程序池标识）相同。
在Microsoft Excel上的DCOMcnfg上，我在“启动和激活权限”上设置自定义选项，并将权限添加到：
- IUSR
- IIS_IUSRS
- Mywebsite（networking应用程序）
这是代码的一部分，但是其中的一个重要部分：
所以这就是为了启动Python代码而在玉中写的部分：
.container-fluid .row .grid-12 .jumbotron h1 Test Tool p Testing for web application development .row .section.group .col.span_2_of_3 h1 Step 1 p For select the Input Data File, please press the "Select Data Input" button form(action='upload', method='post', enctype='multipart/form-data') .table input.filestyle(type='file', name = 'file', data-buttonname='btn-primary', data-buttonText= 'Select Data File', data-iconName= 'fa fa-database', data-buttonBefore='true', data-placeholder = 'No File') .table span.btn.btn-primary.btn-file | Upload span.fa.fa-cloud-upload.fa-1x.pull-left input(type='submit')
所以当用户按下button时，上传的文件就被上传了，但是首先Python代码调用另外一个例程，打开一个excel并做一些事情
import os from QPX_Test import app from flask import Flask, render_template, request, redirect, url_for, send_from_directory, after_this_request from werkzeug import secure_filename from win32com.client import Dispatch import pythoncom import process_excel main_path = os.path.join(os.path.dirname(os.path.abspath(__file__)), 'Server') # Initialize the Flask application # app = Flask(__name__) # This is the path to the upload directory app.config['UPLOAD_FOLDER'] = main_path # These are the extension that we are accepting to be uploaded app.config['ALLOWED_EXTENSIONS'] = set(['xls', 'xlsm','xlsx']) # For a given file, return whether it's an allowed type or not def allowed_file(filename): return '.' in filename and \ filename.rsplit('.', 1)[1] in app.config['ALLOWED_EXTENSIONS'] # This route will show a form to perform an AJAX request # jQuery is loaded to execute the request and update the # value of the operation @app.route('/up') def index(): return render_template('upload.jade') # Route that will process the file upload @app.route('/upload', methods=['POST']) def upload(): # Get the name of the uploaded file file = request.files['file'] # Check if the file is one of the allowed types/extensions if file and allowed_file(file.filename): # Make the filename safe, remove unsupported chars filename = secure_filename(file.filename) # Move the file form the temporal folder to # the upload folder we setup file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename)) # Redirect the user to the uploaded_file route, which # will basicaly show on the browser the uploaded file #return redirect(url_for('uploaded_file', # filename=filename)) variable_forsave = os.path.join(main_path, filename) filename_save= os.path.join(main_path, 'Test.xlsm') # Select Excel File and Save Route into System process_excel.up_route(variable_forsave, 'C:\inetpub\wwwroot\MyWebSite\Tool\Main System', 'System','B1') return render_template('webtools_petro.jade') # after save the file do something # This route is expecting a parameter containing the name # of a file. Then it will locate that file on the upload # directory and show it on the browser, so if the user uploads # an image, that image is going to be show after the upload #@app.route('/static/uploads/<filename>') #def uploaded_file(filename): # return send_from_directory(app.config['UPLOAD_FOLDER'], # filename)
最后打开程序，做一些事情
import os import win32com.client from QPX_Test import app from flask import Flask, render_template, request, redirect, url_for, send_from_directory, after_this_request from werkzeug import secure_filename from win32com.client import Dispatch import pythoncom import upload from flask import send_file import StringIO pythoncom.OleInitialize() def up_route(variabletosave, forsave, sheetsave, rangesave): pythoncom.CoInitialize () xlApp = win32com.client.Dispatch('Excel.Application') xlWb = xlApp.Workbooks.Open(forsave) xlSht = xlWb.WorkSheets(sheetsave) xlSht.Range(rangesave).value= variabletosave xlApp.visible = True xlWb.Saved = 0 xlWb.Save() xlWb.Close(SaveChanges=True) xlApp.application.Quit()
所以我认为这个问题发生在Python尝试打开excel而没有权限的时候，有一种方法可以把Python的权限？
编辑在这里———————————————— ——————
好，所以我创build了一个新的应用程序只用于testing…
'指数
extends layout block content .jumbotron h1 Excel Test p.lead Testing the Privileges Features p Current directory {{ testfile }} form(action='test', method='post', enctype='multipart/form-data') button(type="submit)
很简单
和views.py
import os, sys from datetime import datetime from flask import render_template from flask import request from Test_Excel_Python import app from Test_Excel_Python import Excel_test import win32com.client from werkzeug import secure_filename from win32com.client import Dispatch import pythoncom import StringIO app.debug = True Folder_File= os.path.dirname(os.path.abspath(sys.argv[0])) Folder_Excel_Files='Test_Excel_Python\Excel Files' File_open = 'Test File' File_Suffix= 'xlsx' Real_Excel_Route= os.path.join(Folder_File, Folder_Excel_Files, File_open + "." + File_Suffix) @app.route('/') @app.route('/home') def home(): """Renders the home page.""" return render_template( 'index.jade', title='Home Page', year=datetime.now().year, testfile=Real_Excel_Route ) @app.route('/test', methods=['POST']) def test(): #Excel_test.Excel_Open #'esto es un test', Real_Excel_Route, 'Prueba','A1') pythoncom.CoInitialize () xlApp = win32com.client.Dispatch('Excel.Application') xlWb = xlApp.Workbooks.Open('C:\inetpub\wwwroot\MyTestExcel\Test_Excel_Python\Excel Files\Test File.xlsx') xlSht = xlWb.WorkSheets('Sheet1') xlSht.Range('A1').value= 'Testing Write here' xlApp.visible = True xlWb.Saved = 0 xlWb.Save() xlWb.Close(SaveChanges=True) xlApp.application.Quit() return render_template('index.jade')
和webconfig是非常简单的
<?xml version="1.0" encoding="UTF-8"?> <configuration> <system.webServer> <handlers> <add name="FlaskHandler" path="*" verb="*" modules="FastCgiModule" scriptProcessor="C:\Anaconda2\python.exe|C:\inetpub\wwwroot\MyTestExcel\wfastcgi.py" resourceType="Unspecified" /> </handlers> <rewrite> </rewrite> </system.webServer> </configuration>
像第一个程序一样，此例程在Visual Studio 2015（正常）上正常工作，并访问Localhost：5000
但是，当我尝试使用IIS本地主机：82这个错误出现：
Error occurred: Traceback (most recent call last): File "C:\inetpub\wwwroot\MyTestExcel\wfastcgi.py", line 736, in main result = handler(record.params, response.start) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1836, in __call__ return self.wsgi_app(environ, start_response) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1820, in wsgi_app response = self.make_response(self.handle_exception(e)) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1403, in handle_exception reraise(exc_type, exc_value, tb) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1817, in wsgi_app response = self.full_dispatch_request() File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1477, in full_dispatch_request rv = self.handle_user_exception(e) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1381, in handle_user_exception reraise(exc_type, exc_value, tb) File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1475, in full_dispatch_request rv = self.dispatch_request() File "C:\Anaconda2\lib\site-packages\flask\app.py", line 1461, in dispatch_request return self.view_functions[rule.endpoint](**req.view_args) File ".\Test_Excel_Python\views.py", line 64, in test xlWb = xlApp.Workbooks.Open('C:\inetpub\wwwroot\MyTestExcel\Test_Excel_Python\Excel Files\Test File.xlsx') File "<COMObject <unknown>>", line 8, in Open com_error: (-2147352567, 'Exception occurred.', (0, u'Microsoft Excel', u"Microsoft Excel cannot access the file 'C:\\inetpub\\wwwroot\\MyTestExcel\\Test_Excel_Python\\Excel Files\\Test File.xlsx'. There are several possible reasons:\n\n\u2022 The file name or path does not exist.\n\u2022 The file is being used by another program.\n\u2022 The workbook you are trying to save has the same name as a currently open workbook.", u'xlmain11.chm', 0, -2146827284), None) StdOut: StdErr:
我已经尝试添加“xlApp.Interactive = False”，但问题是持久性的，我改变了本地onnly的应用程序身份进行testing，当然这最后的变化“拒绝访问”的问题消失。
我将APPTOOL \ appname添加到安全文件夹读/写访问权限。
请帮助，这是如此令人沮丧！ 🙁
find解决scheme!!!，f **** bug arrrggggg im很开心/生气：
The solution for this appalling BUG in Microsoft IIS & Excel is terrific: Create directory "C:\Windows\SysWOW64\config\systemprofile\Desktop " (for 64 bit Windows) or "C:\Windows\System32\config\systemprofile\Desktop " (for 32 bit Windows) Set Full control permissions for directory Desktop (for example in Win7 & IIS 7 & DefaultAppPool set permissions for user "IIS AppPool\DefaultAppPool")
什么是微软！ 2010解决scheme！