openpyxl KeyError工作表{0}不存在
我知道你可能看过这个标题，但请不要标记为重复，因为我的错误是不同的。 我使用openpyxl比较程序，并使用tkinter使UI更友好。 这是我的代码：
import openpyxl from tkinter import * from tkinter.filedialog import askopenfilename from openpyxl.utils import get_column_letter, column_index_from_string f1 = '' f2 = '' sheet1 = '' sheet2 = '' root = Tk() root.configure(background='light green') root.geometry("500x500") root.wm_title("BananaCell") e1 = Text(root, width=15, height=1) e1.pack() e1.place(x=70, y=150) e2 = Text(root, width=15, height=1) e2.pack() e2.place(x=300, y=150) def destroy(): root.destroy() def get_1(): inputValue = e1.get("1.0", "end-1c") print(inputValue) def get_2(): inputValue2 = e2.get("1.0", "end-1c") print(inputValue2) bf = Button(root, text="Enter", width=6, height=0, command=get_1) bf.pack() bf.place(x=15, y=147) bf = Button(root, text="Enter", width=6, height=0, command=get_2) bf.pack() bf.place(x=430, y=147) def askForFileName1(): global f1 f1 = askopenfilename(title="Select Workbook 1") print(str(f1)) def askForFileName2(): global f2 f2 = askopenfilename(title="Select Workbook 2") print(str(f2)) sheet1 = e1.get("1.0", "end-1c") sheet2 = e2.get("1.0", "end-1c") b = Button(root, text="Workbook 1", width=12, height=2, command=askForFileName1) b.pack() b.place(x=100, y=100) b2 = Button(root, text="Workbook 2", width=12, height=2, command=askForFileName2) b2.pack() b2.place(x=300, y=100) mainloop() wb = openpyxl.load_workbook(str(f1)) wb1 = openpyxl.load_workbook(str(f2)) ws = wb.get_sheet_by_name(str(sheet1)) ws1 = wb1.get_sheet_by_name(str(sheet2)) col1 = input('Column letter from Sheet 1 to compare from: ') col2 = input('Column letter from Sheet 2 to compare from: ') for (col, col_1) in zip(ws.iter_cols(min_col = column_index_from_string(col1), max_col=column_index_from_string(col1)), ws1.iter_cols(min_col = column_index_from_string(col2), max_col=column_index_from_string(col2))): for (cell, cell_1) in zip(col, col_1): if cell.value != cell_1.value and cell.row == cell_1.row: print('Row ' + str(cell.row) + ' ' + str(cell.value) + ' is not equal to ' + str(cell_1.value) + ' ' + 'Row ' + str(cell_1.row)) exit_if = input('Press x to exit when you\'re ready: ') 一切都运行良好，直到我到达行： ws = wb.get_sheet_by_name(str(sheet1)) 。 之后，它给了我错误：
raise KeyError("Worksheet {0} does not exist.".format(key)) KeyError: 'Worksheet does not exist.'
谁能解决这个问题？ 任何帮助将非常感激。
def get_1(): global sheet1 sheet1 = e1.get("1.0", "end-1c") print(sheet1) def get_2(): global sheet2 sheet2 = e2.get("1.0", "end-1c") print(sheet2)
当你调用下面的行
sheet1 = e1.get("1.0", "end-1c") sheet2 = e2.get("1.0", "end-1c")
那时候，e1和e2里什么也没有。 所以你必须在像文件名一样的函数中调用它。
而且，你应该使用Entry小部件来获取input