用循环openpyxl iter_rows(min_row,max_row)
为什么iter_rows
总是说must be str, not int
? 我只是试图把我的第一个值min_row
和max_row
。
from openpyxl import load_workbook from itertools import islice wb = load_workbook('xyz.xlsx') ws1 = wb['Sheet1'] lst = ['2','2'] limit = 2 for i in islice(lst,limit): row = ws1.iter_rows(min_row=i,max_row=i)
我试着在这里finditer_rows
min_row
max_row
铸造的想法,但是,我只是得到相同的错误和Worksheet object has no attribute
引用错误是
line 509, in iter_rows max_row += row_offset
iter_rows
方法期望min_row
和max_row
input参数是整数。 所以试试这个:
from openpyxl import load_workbook from itertools import islice wb = load_workbook('xyz.xlsx') ws1 = wb['Sheet1'] lst = [2,2] limit = 2 for i in islice(lst,limit): row = ws1.iter_rows(min_row=i,max_row=i)
注意 :通过使用命令help(ws1.iter_rows)
或help(openpyxl.worksheet.worksheet.Worksheet.iter_rows)
查询文档string,您可以获得iter_rows
方法的完整使用说明。 在文档string中,您可以find说明:
:param min_row: smallest row index (1-based index) :type min_row: int :param max_row: smallest row index (1-based index) :type max_row: int