线程“main”中的exceptionjava.lang.IllegalArgumentException：表索引（0）超出范围（0 ..- 1）

我想阅读在Java中使用apache poi api 2010年的Excel文件…但它给了我一个错误线程“主”java.lang.IllegalArgumentExceptionexception：表索引（0）超出范围（0 ..- 1 ）我正在使用xssf，但如果我想从旧格式的Excel中获取数据，那么它通过唱HSSF工作正常..我不知道是怎么回事XSSF ..这里是我的代码..plz帮助我。

import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.InputStream; import java.util.Iterator; import org.apache.poi.ss.usermodel.Cell; import org.apache.poi.ss.usermodel.Row; import org.apache.poi.xssf.usermodel.XSSFCell; import org.apache.poi.xssf.usermodel.XSSFRichTextString; import org.apache.poi.xssf.usermodel.XSSFRow; import org.apache.poi.xssf.usermodel.XSSFSheet; import org.apache.poi.xssf.usermodel.XSSFWorkbook; /** * This java program is used to read the data from a Excel file and display them * on the console output. * * @author dhanago */ public class xssff { /** Creates a new instance of POIExcelReader */ public xssff() { } /** * This method is used to display the Excel content to command line. * * @param xlsPath */ @SuppressWarnings("unchecked") public void displayFromExcel(String xlsPath) { InputStream inputStream = null; try { inputStream = new FileInputStream(xlsPath); } catch (FileNotFoundException e) { System.out.println("File not found in the specified path."); e.printStackTrace(); } XSSFWorkbook workBook = new XSSFWorkbook(); XSSFSheet sheet = workBook.getSheetAt(1); Iterator<Row> rows = sheet.rowIterator(); while (rows.hasNext()) { XSSFRow row = (XSSFRow) rows.next(); // display row number in the console. System.out.println(); // once get a row its time to iterate through cells. Iterator<Cell> cells = row.cellIterator(); while (cells.hasNext()) { XSSFCell cell = (XSSFCell) cells.next(); /* * Now we will get the cell type and display the values * accordingly. */ switch (cell.getCellType()) { case XSSFCell.CELL_TYPE_NUMERIC: { // cell type numeric. System.out.print(cell.getNumericCellValue() + "\t\t\t"); break; } case XSSFCell.CELL_TYPE_STRING: { // cell type string. XSSFRichTextString richTextString = cell .getRichStringCellValue(); System.out.print(richTextString.getString() + "\t\t\t"); break; } default: { // types other than String and Numeric. System.out.println("Type not supported."); break; } } } } } /** * The main executable method to test displayFromExcel method. * * @param args */ public static void main(String[] args) { xssff poiExample = new xssff(); String xlsPath = "c://temp//data.xlsx"; poiExample.displayFromExcel(xlsPath); } } 

Answer 1

好吧，我发现你的问题，你正在创build一个没有床单的新书

 XSSFWorkbook workBook = new XSSFWorkbook(); XSSFSheet sheet = workBook.getSheetAt(1); //error here, the workBook book has NO sheets! 

您应该在InputStream中创build书籍

 XSSFWorkbook workBook = WorkbookFactory.create(new PushbackInputStream(inputStream)); XSSFSheet sheet = workBook.getSheetAt(1); 

或者更简单，只需通过文件名来创build书：

 XSSFWorkbook workBook = new XSSFWorkbook(xlsPath); XSSFSheet sheet = workBook.getSheetAt(1); 

Answer 2

尝试这个：

 // Create Workbook instance holding reference to .xlsx file XSSFWorkbook workbook = new XSSFWorkbook(); XSSFSheet sheet = createSheet(workbook, "Sheet 1", false); XSSFRow row1 = sheet.createRow(0); 

那function是：

  private static XSSFSheet createSheet(XSSFWorkbook wb, String prefix, boolean isHidden) { XSSFSheet sheet = null; int count = 0; for (int i = 0; i < wb.getNumberOfSheets(); i++) { String sName = wb.getSheetName(i); if (sName.startsWith(prefix)) count++; } if (count > 0) { sheet = wb.createSheet(prefix + count); } else sheet = wb.createSheet(prefix); if (isHidden) wb.setSheetHidden(wb.getNumberOfSheets() - 1, XSSFWorkbook.SHEET_STATE_VERY_HIDDEN); return sheet; }