获取Googlesearch的url结果时出错。

我是VBA的新手,我认为尝试编写代码是最好的编码方式。 无论如何,我试图编写一个macros,将获得谷歌search结果的第一个url,但我得到错误的Object variable or With block variable not setsearch结果为0时Object variable or With block variable not set ,其余的操作被跳过。 这是错误图像:

http://i.stack.imgur.com/ltHUL.jpg

这是我使用的代码:

 Sub XMLHTTP() Dim url As String, lastRow As Long Dim XMLHTTP As Object, html As Object, objResultDiv As Object, objH3 As Object, link As Object Dim start_time As Date Dim end_time As Date lastRow = Range("A" & Rows.Count).End(xlUp).Row Dim cookie As String Dim result_cookie As String start_time = Time Debug.Print "start_time:" & start_time For i = 2 To lastRow url = "https://www.google.co.in/search?q=" & Cells(i, 1) & "&rnd=" & WorksheetFunction.RandBetween(1, 10000) Set XMLHTTP = CreateObject("MSXML2.serverXMLHTTP") XMLHTTP.Open "GET", url, False XMLHTTP.setRequestHeader "Content-Type", "text/xml" XMLHTTP.setRequestHeader "User-Agent", "Mozilla/5.0 (Windows NT 6.1; rv:25.0) Gecko/20100101 Firefox/25.0" XMLHTTP.send Set html = CreateObject("htmlfile") html.body.innerHTML = XMLHTTP.ResponseText Set objResultDiv = html.getelementbyid("rso") Set objH3 = objResultDiv.getElementsByTagName("H3")(0) Set link = objH3.getElementsByTagName("a")(0) str_text = Replace(link.innerHTML, "<EM>", "") str_text = Replace(str_text, "</EM>", "") Cells(i, 2) = str_text Cells(i, 3) = link.href DoEvents Next end_time = Time Debug.Print "end_time:" & end_time Debug.Print "done" & "Time taken : " & DateDiff("n", start_time, end_time) MsgBox "done" & "Time taken : " & DateDiff("n", start_time, end_time) End Sub 

任何人都可以帮我吗?

这里是相同方法的简化代码。

 Sub xmlHttp() Dim url As String, lastRow As Long, XMLHTTP As Object, html As Object, objResultDiv As Object, objH3 As Object, link As Object lastRow = Range("A" & Rows.Count).End(xlUp).Row For i = 2 To lastRow url = "https://www.google.co.in/search?q=" & Cells(i, 1) Set xmlHttp = CreateObject("MSXML2.XMLHTTP") xmlHttp.Open "GET", URL, False xmlHttp.setRequestHeader "Content-Type", "text/xml" xmlHttp.send Set html = CreateObject("htmlfile") html.body.innerHTML = xmlHttp.ResponseText Set objResultDiv = html.getelementbyid("rso") numb_H3 = objResultDiv.getElementsByTagName("H3").Length If numb_H3 > 0 Then Set objH3 = objResultDiv.getElementsByTagName("H3")(0) Set link = objH3.getElementsByTagName("a")(0) Range(i, 2) = link Else End If DoEvents Next End Sub 

在零结果的情况下,H3是空的,所以像这样修改你的代码来处理这种情况

  Set html = CreateObject("htmlfile") html.body.innerhtml = XMLHTTP.ResponseText Set objResultDiv = html.getelementbyid("rso") **numb_H3 = objResultDiv.getElementsByTagName("H3").Length** **If numb_H3 > 0 Then** Set objH3 = objResultDiv.getElementsByTagName("H3")(0) Set link = objH3.getElementsByTagName("a")(0) str_text = Replace(link.innerhtml, "<EM>", "") str_text = Replace(str_text, "</EM>", "") Cells(i, 2) = str_text Cells(i, 3) = link.href **Else** **End If** DoEvents 

下一个

一个简单的解决方法 – 虽然不是最好的 – 是跳过错误。

尝试以下修改:

 start_time = Time Debug.Print "start_time:" & start_time On Error Resume Next '--Add this part. For i = 2 To lastRow 

其他选项包括一个真正的error handling部分,当你的search没有返回任何东西时返回一个值。

让我们知道这是否有帮助。