Excel创build一系列相同的值？
我想知道是否有一种方法可以简化IRR计算？ 例如，我有稳定的收入$ 500 /月，我想看到6个月，12个月，18个月等内部收益率。
目前，我必须创build三列，一列有五行$ 500，一行有$ 500 $ 12等
有没有办法使计算变得单调？
PS实际上有不同的最后付款价值，所以我不能创build12行，并select相同的值的子集。
EDITED在阅读lori-m的评论之后，我在我的回复中增加了更多的内容来说明由Excel RATE函数内部执行的RATE计算
原始回复
我假定最后一个值是负值，因为您至less需要一个负值才能findIRR 。
当年金支付金额不变时，您可以select使用Excel RATE函数来计算内部收益率
RATE函数接受下列值
=速率（NPER，PMT，PV，[FV]，types）
NPER将是你的情况6,12,18的时期的数量
PMT是这种情况下的定期付款500
如果PV是现金stream量，那么PV是现值年金，那么您需要将其指定为负值
FV是残值
使用RATE函数要求以下值中的至less一个或最多两个必须是负FV，PV或PMT
然而，从你所写的内容来看，甚至可能没有负现金stream，从而导致不能使用IRR或RATE函数
以下文字显示RATE函数如何使用TVM方程式计算内部收益率或简单地计算收益率
Newton Raphson Method IRR Calculation with TVM equation = 0 TVM Eq. 1: PV(1+i)^N + PMT(1+i*type)[(1+i)^N -1]/i + FV = 0 f(i) = 0 + 500 * (1 + i * 0) [(1+i)^6 - 1)]/i + -2500 * (1+i)^6 f'(i) = (500 * ( 6 * i * (1 + i)^(5+0) - (1 + i)^6) + 1) / (i * i)) + 6 * -2500 * (1+0.1)^5 i0 = 0.1 f(i1) = -571.0975 f'(i1) = -14420.4 i1 = 0.1 - -571.0975/-14420.4 = 0.0603965562675 Error Bound = 0.0603965562675 - 0.1 = 0.039603 > 0.000001 i1 = 0.0603965562675 f(i2) = -63.1212 f'(i2) = -11318.2776 i2 = 0.0603965562675 - -63.1212/-11318.2776 = 0.0548196309075 Error Bound = 0.0548196309075 - 0.0603965562675 = 0.005577 > 0.000001 i2 = 0.0548196309075 f(i3) = -1.1104 f'(i3) = -10921.6385 i3 = 0.0548196309075 - -1.1104/-10921.6385 = 0.0547179582964 Error Bound = 0.0547179582964 - 0.0548196309075 = 0.000102 > 0.000001 i3 = 0.0547179582964 f(i4) = -0.0004 f'(i4) = -10914.4953 i4 = 0.0547179582964 - -0.0004/-10914.4953 = 0.0547179250235 Error Bound = 0.0547179250235 - 0.0547179582964 = 0 < 0.000001 IRR = 5.47% Newton Raphson Method IRR Calculation with TVM equation = 0 TVM Eq. 2: PV + PMT(1+i*type)[1-{(1+i)^-N}]/i + FV(1+i)^-N = 0 f(i) = -2500 + 500 * (1 + i * 0) [1 - (1+i)^-6)]/i + 0 * (1+i)^-6 f'(i) = (-500 * (1+i)^-6 * ((1+i)^6 - 6 * i - 1) /(i*i)) + (0 * -6 * (1+i)^(-6-1)) i0 = 0.1 f(i1) = -322.3697 f'(i1) = -4842.0856 i1 = 0.1 - -322.3697/-4842.0856 = 0.0334233887655 Error Bound = 0.0334233887655 - 0.1 = 0.066577 > 0.000001 i1 = 0.0334233887655 f(i2) = 178.1297 f'(i2) = -6438.6863 i2 = 0.0334233887655 - 178.1297/-6438.6863 = 0.0610889228796 Error Bound = 0.0610889228796 - 0.0334233887655 = 0.027666 > 0.000001 i2 = 0.0610889228796 f(i3) = -49.7272 f'(i3) = -5702.834 i3 = 0.0610889228796 - -49.7272/-5702.834 = 0.0523691914645 Error Bound = 0.0523691914645 - 0.0610889228796 = 0.00872 > 0.000001 i3 = 0.0523691914645 f(i4) = 18.7303 f'(i4) = -5922.4426 i4 = 0.0523691914645 - 18.7303/-5922.4426 = 0.055531790412 Error Bound = 0.055531790412 - 0.0523691914645 = 0.003163 > 0.000001 i4 = 0.055531790412 f(i5) = -6.4397 f'(i5) = -5841.5461 i5 = 0.055531790412 - -6.4397/-5841.5461 = 0.054429394433 Error Bound = 0.054429394433 - 0.055531790412 = 0.001102 > 0.000001 i5 = 0.054429394433 f(i6) = 2.2892 f'(i6) = -5869.581 i6 = 0.054429394433 - 2.2892/-5869.581 = 0.0548194083235 Error Bound = 0.0548194083235 - 0.054429394433 = 0.00039 > 0.000001 i6 = 0.0548194083235 f(i7) = -0.8044 f'(i7) = -5859.6427 i7 = 0.0548194083235 - -0.8044/-5859.6427 = 0.0546821305725 Error Bound = 0.0546821305725 - 0.0548194083235 = 0.000137 > 0.000001 i7 = 0.0546821305725 f(i8) = 0.2838 f'(i8) = -5863.1383 i8 = 0.0546821305725 - 0.2838/-5863.1383 = 0.0547305377303 Error Bound = 0.0547305377303 - 0.0546821305725 = 4.8E-5 > 0.000001 i8 = 0.0547305377303 f(i9) = -0.1 f'(i9) = -5861.9054 i9 = 0.0547305377303 - -0.1/-5861.9054 = 0.0547134792018 Error Bound = 0.0547134792018 - 0.0547305377303 = 1.7E-5 > 0.000001 i9 = 0.0547134792018 f(i10) = 0.0352 f'(i10) = -5862.3398 i10 = 0.0547134792018 - 0.0352/-5862.3398 = 0.054719491928 Error Bound = 0.054719491928 - 0.0547134792018 = 6.0E-6 > 0.000001 i10 = 0.054719491928 f(i11) = -0.0124 f'(i11) = -5862.1867 i11 = 0.054719491928 - -0.0124/-5862.1867 = 0.0547173727531 Error Bound = 0.0547173727531 - 0.054719491928 = 2.0E-6 > 0.000001 i11 = 0.0547173727531 f(i12) = 0.0044 f'(i12) = -5862.2407 i12 = 0.0547173727531 - 0.0044/-5862.2407 = 0.0547181196735 Error Bound = 0.0547181196735 - 0.0547173727531 = 1.0E-6 < 0.000001 IRR = 5.47%