将Excel Formual转换为SQL

我有一个Excel中的公式计算两个date之间有多less个星期日，但我想在SQL中做同样的事情，但不知道如何去做。 你能帮我吗？

=SUM(INT((WEEKDAY(A1-8,1)+B1-A1)/7)) Declare @From as Datetime Declare @To as Datetime Set @From = '7 Jan 2013' Set @To = '18 Mar 2013' SELECT SUM(WEEKDATE(@From-8,1)+ @End-@From)/7)) AS No_Of_Sundays FROM TIME 

谢谢

韦恩

Answer 1

尝试这个：

 SELECT SUM((CASE WHEN DATEPART(dw, @From) = 7 THEN 1 ELSE 0 END) + DATEDIFF(dd, @From, @To) / 7) AS No_Of_Sundays 

正如你所看到的，这取决于本地化 – >在俄罗斯周日是第7天，所以我们检查，如果第一天是星期日

这是另一个解决scheme：

 Declare @From as Datetime Declare @To as Datetime Declare @sundays as INT Set @From = '1/02/2013' Set @To = '28/02/2013' Set @sundays = 0 WHILE (@From <= @To) BEGIN SET @sundays = @sundays + (CASE WHEN DATEPART(dw, @From) = 7 THEN 1 ELSE 0 END) SET @From = DATEADD(dd, 1, @From) END SELECT @sundays 

Answer 2

如果你在sql-server 2005或更高版本，这是一个使用CTE的方法。 这里是一个演示

 declare @From date = '20130107' --'7 Jan 2013' declare @To date = '20130318' --'18 Mar 2013' ;with CTE as ( select 0 number , datename(weekday, @from) dName union all select number+1, datename(weekday,dateadd(day,number+1,@from)) dName from CTE where dateadd(day, number + 1,@from) <= @to and datename(weekday,dateadd(day,number,@from)) <> 'sunday' ) select top(1) (datediff(day,@from,@to) - number )/7 + case when number = 0 and dname <> 'sunday' then 0 else 1 end sundays from CTE order by number desc