打开特定的Excel文件/工作表以获取特定的内容单元位置

我有一个Excel文件列表及其相应的图纸编号。 我需要python去这些工作表，并找出特定内容的单元格位置。 有人可以指出我的代码中的错误？ 提前致谢

import xlrd value = 'Avg.' filename = ('C:/002 Av SW W of 065 St SW 2011-Jul-05.xls', 'C:/003 Avenue SW West of 058 Street SW 2012-Jun-23.xls') sheetnumber = ('505840', '505608') dictionary = dict(zip(filename, sheetnumber)) for item in dictionary: book = xlrd.open_workbook(item) sheet = book.sheet_by_name(dictionary[key]) for row in range(sheet.nrows): for column in range(sheet.ncols): if sheet.cell(row,column).value == value: print row, column 

Answer 1

你不需要制作字典。 遍历zip(filename, sheetnumber) ：

 for name, sheet_name in zip(filename, sheetnumber): book = xlrd.open_workbook(name) sheet = book.sheet_by_name(sheet_name) for row in range(sheet.nrows): for column in range(sheet.ncols): if sheet.cell(row,column).value == value: print row, column