如何转换DocumentFormat.OpenXML中新表中的每个列

我在将Excel文件转换为XML文件时遇到问题。 当我转换表标签中的信息，它转换在<table1></table1> <table1></table1> <table1></table1>但我需要转换<table1></table1><table2></table2>...代码如下。

 private DataTable ReadExcelFile(string filename) { // Initialize an instance of DataTable DataTable dt = new DataTable(); try { // Use SpreadSheetDocument class of Open XML SDK to open excel file using (SpreadsheetDocument spreadsheetDocument = SpreadsheetDocument.Open(filename, false)) { // Get Workbook Part of Spread Sheet Document WorkbookPart workbookPart = spreadsheetDocument.WorkbookPart; // Get all sheets in spread sheet document // IEnumerable Interface // Exposes an enumerator, which supports a simple iteration over a non-generic collection. IEnumerable<Sheet> sheetcollection = spreadsheetDocument.WorkbookPart.Workbook.GetFirstChild<Sheets>().Elements<Sheet>(); // Get relationship Id string relationshipId = sheetcollection.First().Id.Value; // Get sheet1 Part of Spread Sheet Document WorksheetPart worksheetPart = (WorksheetPart)spreadsheetDocument.WorkbookPart.GetPartById(relationshipId); // Get Data in Excel file SheetData sheetData = worksheetPart.Worksheet.Elements<SheetData>().First(); IEnumerable<Row> rowcollection = sheetData.Descendants<Row>(); if (rowcollection.Count() == 0) { return dt; } // Add columns foreach (Cell cell in rowcollection.ElementAt(0)) { dt.Columns.Add(GetValueOfCell(spreadsheetDocument, cell)); } // Add rows into DataTable foreach (Row row in rowcollection) { DataRow temprow = dt.NewRow(); int columnIndex = 0; foreach (Cell cell in row.Descendants<Cell>()) { // Get Cell Column Index int cellColumnIndex = GetColumnIndex(GetColumnName(cell.CellReference)); if (columnIndex < cellColumnIndex) { do { temprow[columnIndex] = string.Empty; columnIndex++; } while (columnIndex < cellColumnIndex); } temprow[columnIndex] = GetValueOfCell(spreadsheetDocument, cell); columnIndex++; } // Add the row to DataTable // the rows include header row dt.Rows.Add(temprow); } } // Here remove header row dt.Rows.RemoveAt(0); return dt; } catch (IOException ex) { throw new IOException(ex.Message); } } private static string GetValueOfCell(SpreadsheetDocument spreadsheetdocument, Cell cell) { // Get value in Cell SharedStringTablePart sharedString = spreadsheetdocument.WorkbookPart.SharedStringTablePart; if (cell.CellValue == null) { return string.Empty; } string cellValue = cell.CellValue.InnerText; // The condition that the Cell DataType is SharedString if (cell.DataType != null && cell.DataType.Value == CellValues.SharedString) { return sharedString.SharedStringTable.ChildElements[int.Parse(cellValue)].InnerText; } else { return cellValue; } } private string GetColumnName(string cellReference) { // Create a regular expression to match the column name of cell Regex regex = new Regex("[A-Za-z]+"); Match match = regex.Match(cellReference); return match.Value; } private int GetColumnIndex(string columnName) { int columnIndex = 0; int factor = 1; // From right to left for (int position = columnName.Length - 1; position >= 0; position--) { // For letters if (Char.IsLetter(columnName[position])) { columnIndex += factor * ((columnName[position] - 'A') + 1) - 1; factor *= 26; } } return columnIndex; } public string GetXML(string filename) { using (DataSet ds = new DataSet()) { ds.Tables.Add(this.ReadExcelFile(filename)); return ds.GetXml(); } } 

有人可以帮我解决这个问题吗？ 或者任何想法如何创build自定义标签？

提前致谢。