这可能是一个容易的,但我有这个Excel VBA的macros,我试图分裂两个整数,我最终以一个整数,即使应该有一个逗号在那里。 例如278/101 = 3.虽然它确实是2,75而不是3,为什么呢? macros很简单,就像这样: Dim intFull, intLow , intDivided as Integer intFull = 278 intLow = 101 intDivided = intFull \ intLow
我有期刊文章,每卷包含三个问题。 有没有一个公式增加1.1,1.2,1.3,然后跳转到2.1,2.2,2.3?
我想创build一个大小为50的数组,在0到20之间的随机数的vba,然后提取数组,重复在该数组到另一个数组。 Sub Problem10() Dim numbers() As Double, odd() As Double, even() As Double, five() As Double, repeating() As Double, x As Integer, i As Integer, sOdd As Integer, sEven As Integer, sFive As Integer, sNumbers As Integer, sRepeating As Integer, y As Integer, listed As Boolean sRepeating = 0 sNumbers = 50 For i = […]
固定string会比整数使用更less的内存吗? Public Type MyType UserID As Integer 'All My User IDs are less than 7 integers in length UserID As String * 7 ''Will a Fixed String use less memory than an Integer? End Type 有没有办法在VBA程序中testing?