使用EPplus将多次插入相同的图像到Excel中

我想用EPplus方法多次插入相同的图像到Excel中。 我在线研究并尝试了此链接中的方法（ 使用EPPlus将图像添加到Excel中 ），但在此行中收到以下错误“ 图像 集合中的名称已存在” ：

var picture = ws.Drawings.AddPicture(a.ToString(), repeatimage); 

这是我的代码：

 public void ExportToExcel() { //for export ExcelPackage objExcelPackage = new ExcelPackage(); //create new workbook string[] filesindirectory = Directory.GetDirectories(Server.MapPath("~/Folder")); string repeatimagepath=@"C:\Users\user\Desktop\Project\Project1\Project1\NewProject\NewProject\Image\repeatimage.png"; Bitmap repeatimage= new Bitmap(repeatimagepath); int count = 0; int count1 = 0; int x = 25; int finalValue = 0; foreach (string subdir in filesindirectory) { count++; string[] splitter = subdir.Split('\\'); string folderName = splitter[splitter.Length - 1]; ExcelWorksheet ws = objExcelPackage.Workbook.Worksheets.Add(folderName); //create new worksheet count1 = 0; foreach (string img in Directory.GetFiles(subdir)) { count1++; System.Web.UI.WebControls.Image TEST_IMAGE = new System.Web.UI.WebControls.Image(); System.Drawing.Image myImage = System.Drawing.Image.FromFile(img); var pic = ws.Drawings.AddPicture(count1.ToString(), myImage); **for (int a = 0; a < 5; a++) { var picture = ws.Drawings.AddPicture(a.ToString(), repeatimage); picture.SetPosition(a * 5, 0, 2, 0); }** // Row, RowoffsetPixel, Column, ColumnOffSetPixel if (count1 > 1) { pic.SetPosition(finalValue, 0, 2, 0); finalValue += (x + 1); // Add 1 to have 1 row of empty row } else { pic.SetPosition(count1, 0, 2, 0); finalValue = (count1 + x) + 1; // Add 1 to have 1 row of empty } myImage.Dispose(); repeatimage.Dispose(); } } var filepath = new FileInfo(@"C:\Users\user\Desktop\Test\" + datetime.ToString("dd-MM-yyyy_hh-mm-ss") + ".xlsx"); objExcelPackage.SaveAs(filepath); } 

问题：如何使用EPplus将相同的图像多次插入到excel中？

请帮助我，谢谢。

Answer 1

错误已经告诉你答案
这行count1是1

 var pic = ws.Drawings.AddPicture(count1.ToString(), myImage); 

然后这一行

 for (int a = 0; a < 5; a++) { var picture = ws.Drawings.AddPicture(a.ToString(), repeatimage); picture.SetPosition(a * 5, 0, 2, 0); } 

你的a将是0作为图片的名字
你看到错误？